The half angular width of the central maxima in the Fraunhofer diffraction due to a slit of width $\frac{1200}{\sqrt{2}} \ \mu m$ is $45^o$. Then the wavelength of the light is ...... $\mu m$.

  • A
    $600$
  • B
    $1200$
  • C
    $\frac{600}{\sqrt{2}}$
  • D
    $\frac{1200}{\sqrt{2}}$

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